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#include<stdio.h> #include<stdlib.h> #define bool int /* A binary tree node has data, pointer to left child and a pointer to right child */ struct node { int data; struct node* left; struct node* right; }; /* Original example code. Given a tree and a sum, return true if there is a path from the root down to a leaf, such that adding up all the values along the path equals the given sum. Strategy: subtract the node value from the sum when recurring down, and check to see if the sum is 0 when you run out of tree. */ bool hasPathSum_original(struct node* node, int sum) { /* return true if we run out of tree and sum==0 */ if (node == NULL) { return (sum == 0); } else { bool ans = 0; /* otherwise check both subtrees */ int subSum = sum - node->data; /* If we reach a leaf node and sum becomes 0 then return true*/ if ( subSum == 0 && node->left == NULL && node->right == NULL ) return 1; if(node->left) ans = ans || hasPathSum_original(node->left, subSum); if(node->right) ans = ans || hasPathSum_original(node->right, subSum); return ans; } } /* Here is the original example without optimization. You'll see that the algorithm is much cleaner now. Note that this will short-circuit the calls in the line with the return statement. */ bool hasPathSum_revised(struct node* node, int sum) { /* return true if we run out of tree and sum==0 */ if (node == NULL) return (sum == 0); /* otherwise check both subtrees */ int subSum = sum - node->data; return hasPathSum_revised(node->left, subSum) || hasPathSum_revised(node->right, subSum); } /* Find the minimum in the binary tree - without making any assumptions. Call this with an "impossible" minimum at top level. */ int findMin(struct node* node, int min) { if (!node) return min; if (node->data < min) min = node->data; int leftMin = findMin(node->left, min); if(leftMin < min) min = leftMin; int rightMin = findMin(node->right, min); if(rightMin < min) min = rightMin; return min; } /* UTILITY FUNCTIONS */ /* Helper function that allocates a new node with the given data and NULL left and right pointers. */ struct node* newnode(int data) { struct node* node = (struct node*) malloc(sizeof(struct node)); node->data = data; node->left = NULL; node->right = NULL; return(node); } void freetree(struct node* node) { if(!node) return; freetree(node->left); freetree(node->right); free(node); } /* Generate a random full binary tree where every path to a leaf has the totalsum given */ struct node* generatetree(struct node* node, unsigned depth, int totalsum) { if(depth == 0) { node->data = totalsum; return node; } node->data = (rand() % 100) - 50; node->left = newnode(0); node->right = newnode(0); generatetree(node->left, depth-1, totalsum - node->data); generatetree(node->right, depth-1, totalsum - node->data); return node; } void inspecttree(struct node* root, int expected_sum) { printf("Original:\n"); if(hasPathSum_original(root, expected_sum)) printf("There is a root-to-leaf path with sum %d\n", expected_sum); else printf("There is no root-to-leaf path with sum %d\n", expected_sum); printf("Revised:\n"); if(hasPathSum_revised(root, expected_sum)) printf("There is a root-to-leaf path with sum %d\n", expected_sum); else printf("There is no root-to-leaf path with sum %d\n", expected_sum); /* where was INT_MAX defined again :( */ printf("Minimum: %d\n", findMin(root, 60000)); } /* Driver program to test above functions*/ int main() { srand(time(NULL)); int sum = 21; /* Hand constructed binary tree is 10 / \ 8 2 / \ / 3 5 2 */ struct node *root = newnode(10); root->left = newnode(8); root->right = newnode(2); root->left->left = newnode(3); root->left->right = newnode(5); root->right->left = newnode(2); inspecttree(root, sum); freetree(root); root = generatetree(newnode(0), 8, 1000); inspecttree(root, 1000); freetree(root); getchar(); return 0; }
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