kod dla Martyn

// A C++ program for Dijkstra's single source shortest path algorithm.
// The program is for adjacency matrix representation of the graph

#include <limits.h>
#include <stdio.h>
#include <fstream>
#include <iostream>
#include <conio.h>
#include <string>

using namespace std;

// Number of vertices in the graph
#define V 9

// A utility function to find the vertex with minimum distance value, from
// the set of vertices not yet included in shortest path tree
int minDistance(int dist[], bool sptSet[])
{
    // Initialize min value
    int min = INT_MAX, min_index;

    for (int v = 0; v < V; v++)
        if (sptSet[v] == false && dist[v] <= min)
            min = dist[v], min_index = v;

    return min_index;
}

// A utility function to print the constructed distance array
void printSolution(int dist[])
{
    printf("Wezel \t\t Odleglosc\n");
    for (int i = 0; i < V; i++)
        printf("%d \t\t %d\n", i, dist[i]);
}

// Function that implements Dijkstra's single source shortest path algorithm
// for a graph represented using adjacency matrix representation
void dijkstra(int graph[V][V], int src)
{
    int dist[V]; // The output array. dist[i] will hold the shortest
    // distance from src to i

    bool sptSet[V]; // sptSet[i] will be true if vertex i is included in shortest
    // path tree or shortest distance from src to i is finalized

    // Initialize all distances as INFINITE and stpSet[] as false
    for (int i = 0; i < V; i++)
        dist[i] = INT_MAX, sptSet[i] = false;

    // Distance of source vertex from itself is always 0
    dist[src] = 0;

    // Find shortest path for all vertices
    for (int count = 0; count < V - 1; count++) {
        // Pick the minimum distance vertex from the set of vertices not
        // yet processed. u is always equal to src in the first iteration.
        int u = minDistance(dist, sptSet);

        // Mark the picked vertex as processed
        sptSet[u] = true;

        // Update dist value of the adjacent vertices of the picked vertex.
        for (int v = 0; v < V; v++)

            // Update dist[v] only if is not in sptSet, there is an edge from
            // u to v, and total weight of path from src to v through u is
            // smaller than current value of dist[v]
            if (!sptSet[v] && graph[u][v] && dist[u] != INT_MAX
                && dist[u] + graph[u][v] < dist[v])
                dist[v] = dist[u] + graph[u][v];
    }

    // print the constructed distance array
    printSolution(dist);
}

// driver program to test above function
int main(int argc, char* argv[2])
{
    argv[0] == "-i";
    argv[1] == "-o";
    argv[2] == "-s";

    /* Let us create the example graph discussed above */
    int graph[V][V] = { { 0, 4, 0, 0, 0, 0, 0, 8, 0 },
                        { 4, 0, 8, 0, 0, 0, 0, 11, 0 },
                        { 0, 8, 0, 7, 0, 4, 0, 0, 2 },
                        { 0, 0, 7, 0, 9, 14, 0, 0, 0 },
                        { 0, 0, 0, 9, 0, 10, 0, 0, 0 },
                        { 0, 0, 4, 14, 10, 0, 2, 0, 0 },
                        { 0, 0, 0, 0, 0, 2, 0, 1, 6 },
                        { 8, 11, 0, 0, 0, 0, 1, 0, 7 },
                        { 0, 0, 2, 0, 0, 0, 6, 7, 0 } };

    dijkstra(graph, 0);

    if (argc == 1)
    {
        printf("Nie podano argumentow!\n Mozliwe argumenty to: \n-i sciezka do pliku wejsciowego \n-o sciezka do pliku wyjsciowego \n-s miasto startowe \n");
    }
    if (argc >= 2)
    {
        if (argv[0]) {
            printf("wybrano '-i'");
        }
        if (argv[1]) {
            printf("wybrano '-o'");
        }
        if (argv[2]) {
            printf("wybrano '-s'");
        }
        printf("\nPodano liczbe argumentow: %d", argc);
    }

    fstream plik, plik2;
    plik.open("odleglosci.txt", ios::in);
    plik2.open("trasy.txt", ios::out);

    if (plik.good())
    {
        string napis;
        printf("Zawartosc pliku: \n");
        while (!plik.eof())
        {
            getline(plik, napis);
            cout << napis << endl;
        }
        plik.close();
    }
    else printf("Error! Nie udalo otworzyc sie pliku!");


    if (plik2.good())
    {
        for (int i = 0; i < 10; i++)
        {
            plik2 << i << " ";
            plik2.flush();
        }

        plik2.close();
    }

    getchar();

    return 0;
}