Here: BRSET PortM, $04, Here ; Branch, if PM2 is SET, to HERE
    ;code to run when PM2 = LOW ; If we get here PM2 is LOW
          LDAA $00,X        ;Store first value in table into ACCA
          INX               ;Point to the next value stored in the table
          STAA PortT        ;Output the first value of the table stored in ACCA
          LDAA COUNT        ;Load value of count into ACCA
          INCA              ;Increment value stored in ACCA
          STAA COUNT        ;Store Value from A into COUNT
          JSR DELAY         ;Set the delay
          BSET PortM,$02    ;Enables latch
          NOP               ;No op
          NOP               ;No op
          BCLR PortM,$02    ;Disables latch
          LDAB #$08         ;Set value $08 in ACCB
          CBA               ;Compare value in B to A
    Here1:BRCLR PortM, $04, Here1
          BEQ LOOP2         ;If value in B is the same as A branch to loop2
          JMP Here          ;Jump back to beginning of loop here



     Here: BRSET PortM, $04, Here ; Poll for button press
          LDAB  COUNT       ;Load counter value into ACCB
          LDAA  #$0A        ;Compare COUNT to 9
          CBA               ;Compare B (COUNT) to A (9)
          BEQ   NINE        ;Branch to NINE if Equal
          LDAB  COUNT       ;Load Count into ACCB
          LDX   #Table
          ABX               ;Add B to X to offset pointer. Solution in X
          LDAA  $00, X      ;Store new address' value into ACCA
          STAA  PortT       ;Move solution into PortT's address
          BSET  PortM, $02  ;Enable Right latch
          NOP               ;Waste time
          NOP               ;Waste time
          BCLR  PortM, $02  ;Disable Right latch
          LDAB  COUNT       ;Load COUNT into B
          INCB              ;
          STAB  COUNT       ;Incriment COUNT upon completed iteration

          JSR   Delay
          JMP   Here

            ;First lets take care of updating the left latch
            ;If the left display is also a 9 we need to reset it and it's counters along with the right display
     NINE:  LDAA    #$09
            LDAB    COUNT2
            CBA
            BEQ     REDO
            LDX     #Table
            LDAB    COUNT2      ;Load value of COUNT2 into ACCB
            INCB                ;Incriment value of COUNT2
            STAB    COUNT2
            ABX                 ;Add B to X to offset pointer. Solution in X
            LDAA    $00,X       ;Store new address' value into ACCA
            STAA    PortT       ;Move solution into PortT's Address
            BSET    PortM, $01  ;Enable Left latch
            NOP                 ;Waste time
            NOP                 ;Waste time
            BCLR    PortM, $01  ;Disable right latch
            LDAA    #$3F        ;Load binary sequence for ZERO into A
            STAA    PortT       ;Store into PortT's address
            BSET    PortM, $02  ;Enable right latch
            NOP
            NOP
            BCLR    PortM, $02 ;Disable right latch
            JMP     RIGHT

     REDO:  LDAA    $#3F
            STAA    PortT
            BSET    PORTM, $01
            NOP
            NOP
            BCLR    PORTM, $01
            JMP     MAINLOOP


            ;Now lets take care of updating the right latch, which we assume is 9 at this point
     RIGHT: LDAA    #$3F        ;Load bit sequence for ZERO into ACCA
            STAA    PortT       ;Store it into Port T's address
            BSET    PortM, $02  ;Enable Right latch
            NOP                 ;Waste time
            NOP                 ;Waste time
            BCLR    PortM, $02  ;Disable Right latch
            JSR     Delay

            ;If the left display is also a 9 we need to reset it and it's counters along with the right display


            ;So now we should have both displays updated but we need to reset COUNT because it's at 9
            LDAA    #$01
            STAA    COUNT       ;Reset the loop counter
            JMP     Here