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Mar 20th, 2019
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  1. table_user
  2. col1 col2
  3. 123 456
  4. 124 457
  5. 125 458
  6. 126 459
  7. 127 460
  8. 128 461
  9.  
  10. select count(distinct col1) from table_user;
  11.  
  12. select count(distinct col1) from table_user;
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