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- loga = [(912, "Message A1") , (1000, "Message A2") , (988, "Message A3") , (1012, "Message A4") , (1002, "Message A5")]
- logb = [(926, "Message B1") , (1008, "Message B2") , (996, "Message B3") , (1019, "Message B4") , (1100, "Message B5")]
- logc = [(1056,"Message C1") , (1033, "Message C2") , (999, "Message C3") , (1054, "Message C4") , (1086, "Message C5")]
- logs = [loga, logb, logc]
- def find_lowest_i(logs):
- for i in range(len(lst)):
- log = lst(i)
- if len(log) > t = log[0][0]
- if i==0 or t < lowest_t
- lowest_i = i
- lowest_t = t
- return i
- loga = [(912, "Message A1") , (1000, "Message A2") , (988, "Message A3") , (1012, "Message A4") , (1002, "Message A5")]
- logb = [(926, "Message B1") , (1008, "Message B2") , (996, "Message B3") , (1019, "Message B4") , (1100, "Message B5")]
- logc = [(1056,"Message C1") , (1033, "Message C2") , (999, "Message C3") , (1054, "Message C4") , (1086, "Message C5")]
- logs = [loga, logb, logc]
- final=[]
- for log in logs:
- for tup in log:
- final.append(tup[0])
- lowest_number=min(int(x) for x in final)
- return lowest_number
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