Метод простых итераций и Зейделя

#include "pch.h"
#include <iostream>
#include <math.h>
#include <cstdlib>
#include <locale>
#include <iomanip>

using namespace std;
int main()
{
	setlocale(LC_ALL, "Russian");
	double x = 0, x1 = 0, y = 0, y1 = 0, z = 0, z1 = 0, v = 0, v1 = 0, e = 0.001, pogx, pogy, pogz, pogv;
	int k = 1;
	do
	{
		cout.precision(4);
		cout << fixed;
		x1 = x;
		y1 = y;
		z1 = z;
		v1 = v;
		cout << endl << k << "-я итерация." << endl;
		x = (-y1 + z1 - 2 * v1 + 6) / 5;
		y = (x1 + z1 - 2 * v1 - 14) / 6;
		z = (-x1 + y1 + v1 - 3) / 8;
		v = (x1 + y1 + z1 + 5) / 10;
		pogx = abs(x - x1);
		pogy = abs(y - y1);
		pogz = abs(z - z1);
		pogv = abs(v - v1);
		cout.precision(4);
		cout << "x = (-y + z - 2 * v + 6) / 5 = " << x << endl;
		cout << "y = (x + z - 2 * v - 14) / 6 = " << y << endl;
		cout << "z = (-x + y + v - 3) / 8 = " << z << endl;
		cout << "v = (x + y + z + 5) / 10 = " << v << endl;
		cout << "Погрешность для x = " << pogx << endl;
		cout << "Погрешность для y = " << pogy << endl;
		cout << "Погрешность для z = " << pogz << endl;
		cout << "Погрешность для v = " << pogv << endl;
		k++;
	} while (pogx > e || pogy > e || pogz > e || pogv > e);
	system("pause");
	return 0;

}

/*#include "pch.h"
#include <iostream>
#include <math.h>
#include <cstdlib>
#include <locale>
#include <iomanip>

using namespace std;
int main()
{
	setlocale(LC_ALL, "Russian");
	double x = 0, x1 = 0, y = 0, y1 = 0, z = 0, z1 = 0, v = 0, v1 = 0, e = 0.001, pogx,pogy, pogz, pogv;
	int k = 1;
	cout << endl << k << "-я итерация." << endl;
	x = (-y1 + z1 - 2 * v1 + 6) / 5;
	y = (x1 + z1 - 2 * v1 - 14) / 6;
	z = (-x1 + y1 + v1 - 3) / 8;
	v = (x1 + y1 + z1 + 5) / 10;
	pogx = abs(x - x1);
	pogy = abs(y - y1);
	pogz = abs(z - z1);
	pogv = abs(v - v1);
	cout.precision(4);
	cout << fixed;
	cout << "x = (-y + z - 2 * v + 6) / 5 = " << x << endl;
	cout << "y = (x + z - 2 * v - 14) / 6 = " << y << endl;
	cout << "z = (-x + y + v - 3) / 8 = " << z << endl;
	cout << "v = (x + y + z + 5) / 10 = " << v << endl;
	cout << "Погрешность для x = " << pogx << endl;
	cout << "Погрешность для y = " << pogy << endl;
	cout << "Погрешность для z = " << pogz << endl;
	cout << "Погрешность для v = " << pogv << endl;
	k++;
	while (pogx > e || pogy > e || pogz > e || pogv > e)
	{
		cout.precision(4);

		x1 = x;
		y1 = y;
		z1 = z;
		v1 = v;
		cout << endl << k << "-я итерация." << endl;
		x = (-y + z - 2 * v + 6) / 5;
		y = (x + z - 2 * v - 14) / 6;
		z = (-x + y + v - 3) / 8;
		v = (x + y + z + 5) / 10;
		pogx = abs(x - x1);
		pogy = abs(y - y1);
		pogz = abs(z - z1);
		pogv = abs(v - v1);
		cout.precision(4);
		cout << "x = (-y + z - 2 * v + 6) / 5 = " << x << endl;
		cout << "y = (x + z - 2 * v - 14) / 6 = " << y << endl;
		cout << "z = (-x + y + v - 3) / 8 = " << z << endl;
		cout << "v = (x + y + z + 5) / 10 = " << v << endl;
		cout << "Погрешность для x = " << pogx << endl;
		cout << "Погрешность для y = " << pogy << endl;
		cout << "Погрешность для z = " << pogz << endl;
		cout << "Погрешность для v = " << pogv << endl;
		k++;
	};
	system("pause");
	return 0;

}*/