#include <bits/stdc++.h>

using namespace std;

using ll = long long;

const int N = 2000;

bitset<N> b[N], y[N];

void solve() {
    int n;
    cin >> n;
    vector<string> g(n);
    for (int i = 0; i < n; i++) {
        cin >> g[i];
        for (int j = 0; j < n; j++) {
            if (i == j) continue;
            if (g[i][j] == 'B') {
                b[i].set(j);
            } else {
                y[i].set(j);
            }
        }
    }

    vector<ll> cnt(2);
    for (int i = 0; i < n; i++) {
        for (int j = i + 1; j < n; j++) {
            int kek = 0;
            if (g[i][j] == 'B') {
                kek = (y[i] & y[j]).count();
            } else {
                kek = (b[i] & b[j]).count();
            }
            cnt[0] += kek * (kek - 1) / 2;
            cnt[1] += (y[i] & b[j]).count() * (b[i] & y[j]).count();
        }
    }
    cout << cnt[1] /  2 - cnt[0] << endl;
}

int main() {
    ios::sync_with_stdio(false);
    cin.tie(nullptr);
    int T = 1;
    // cin >> T;
    for (int tc = 1; tc <= T; tc++) {
        // cout << "Case #" << tc << ": ";
        solve();
    }
    return 0;
}