nizi suma i parnost/neparnost

#include <stdio.h>
#define MAX 100
int main() {
  int i, n, a[MAX], brNep = 0, brPar = 0, sumNep = 0, sumPar = 0;
  scanf("%d", &n);
  for (i = 0; i < n; ++i)
  scanf("%d", &a[i]);
  for (i = 0; i < n; ++i) {
  if (a[i] % 2) {
  brNep++;
  sumNep += a[i];
  } else {
  brPar++;
  sumPar += a[i];
  }
  }
  printf("Suma parni: %d\nSuma neparni: %d\n", sumPar, sumNep);
  printf("Odnos: %.2f\n", (float)brPar / brNep);
  return 0;
}