tree xor

// Those who cannot remember the past are
// condemned to repeat it (use DP -_-)
// - George Santayana

#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>

using namespace std;
using namespace __gnu_pbds;

#define all(v) v.begin(), v.end()
#define rall(v) v.rbegin(), v.rend()
#define ll long long
#define ull unsigned long long
#define MOD 1000000007
#define PI 3.14159265
#define ceil(a, b) (((a) / (b)) + ((a) % (b) ? 1 : 0))
#define imin INT_MIN
#define imax INT_MAX
#define llmax LLONG_MAX
#define llmin LLONG_MIN
#define inf 2000000000
#define nl '\n'
#define ppcnt __builtin_popcount
#define ppcntll __builtin_popcountll
#define clz __builtin_clz
#define clzll __builtin_clzll
#define ctz __builtin_ctz
#define ctzll __builtin_ctzll
#define modulo(a, b, mod) ((((a) % (mod)) + ((b) % (mod))) % (mod))
#define cnte(v, x) count(all(v), (x))
#define mine(v) min_element(all(v))
#define maxe(v) max_element(all(v))
#define updmin(a, b) a = min(a, b)
#define updmax(a, b) a = max(a, b)
#define finmod(x, m) x = ((x) % (m) + (m)) % m
#define debug(x) cout << "x: " << (x) << nl;
#define debug2(x, y) cout << "x: " << (x) << " y: " << y << nl;
#define ordered_set tree<pair<int, int>, null_type, less<>, rb_tree_tag, tree_order_statistics_node_update>
#define ordered_map tree<int, int, less<>, rb_tree_tag, tree_order_statistics_node_update>

//vector<int> dx = {0, 0, 1, -1, 1, 1, -1, -1}, dy = {1, -1, 0, 0, 1, -1, 1, -1};
//vector<int> dx = {0, 0, 1, -1}, dy = {1, -1, 0, 0};

template<typename T = int> istream& operator>>(istream& in, vector<pair<int, int>>& v){
    for (auto& [x, y] : v) in >> x >> y;
    return in;
}

template<typename T = int> istream& operator>>(istream& in, vector<T>& v){
    for (T& i : v) in >> i;
    return in;
}

template<typename T = int> ostream& operator<<(ostream& out, const vector<T>& v){
    for (const T& x : v)
        out << x << ' ';
    return out;
}

template<typename T = pair<int, int>> ostream& operator << (ostream& out, const vector<pair<int, int>>& v){
    for(auto& [x, y] : v){
        out << x << ' ' << y << nl;
    }
    return out;
}

void Start_Crushing() {
    ios_base::sync_with_stdio(false);
    cin.tie(nullptr);
    cout.tie(nullptr);
#ifndef ONLINE_JUDGE
    freopen("input.txt", "r", stdin);
    freopen("output.txt", "w", stdout);
#endif
}
vector<vector<pair<int, int>>> tree_1, tree_2;
vector<int> one_1, one_2, zero_1, zero_2;
vector<bool> vis;

void dfs(int src, int st, int curr, bool one, vector<vector<pair<int, int>>>& tree){

    for(int bit = 0; bit < 31; bit++){
        if(curr & (1 << bit)){
            (one ? one_1 : one_2)[bit]++;
        }else{
            (one ? zero_1 : zero_2)[bit]++;
        }
    }

    vis[src] = true;

    for(auto& [nxt, wgt] : tree[src]){
        if(not vis[nxt]){
            dfs(nxt, st, curr ^ wgt, one, tree);
        }
    }
}

void solve(){
    int n; cin >> n;
    tree_1.assign(n + 5, vector<pair<int, int>>());
    tree_2.assign(n + 5, vector<pair<int, int>>());

    one_1.resize(32), one_2.resize(32), zero_1.resize(32), zero_2.resize(32);

    for(int i = 0; i < 2; i++){
        for(int j = 0; j < n - 1; j++){
            int u, v, w; cin >> u >> v >> w;
            (i & 1 ? tree_2 : tree_1)[u].emplace_back(v, w);
            (i & 1 ? tree_2 : tree_1)[v].emplace_back(u, w);
        }
    }

    // we should count the number of ways in which we can set this bit to one in both trees
    // and then, I think we can multiply the two frequencies by each others
    for(int i = 1; i <= n; i++){
        vis.assign(n + 5, false);
        dfs(i, i, 0, true, tree_1);
        vis.assign(n + 5, false);
        dfs(i, i, 0, false, tree_2);
    }

    int sum = 0;
    debug(one_1)
    debug(zero_1)
    debug(one_2)
    debug(zero_2)

    for(int i = 1; i <= n; i++){
        for(int j = 1; j <= n; j++){
            for(int k = 1; k <= n; k++){
                if(i == j and j == k)
                    continue;
                cout << i << ' ' << j << ' ' << k << nl;
            }
        }
    }


}

int main(){
    Start_Crushing();

    int t = 1;
//    /*Multiple test cases?*/ cin >> t;
    while (t--) {
        solve();
        if(!t)
            break;
        cout << nl;
    }

//    for(int tc = 1; tc <= t; tc++){
//        cout << "Case #" << tc << ": ";
//        solve();
//        if(tc != t)
//            cout << nl;
//    }

    return 0;
}