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- let k = 1
- let X = map from local index (i,j) to global index k
- for each quadrilateral i
- for each node j in quadrilateral i
- if (i,j) is coincident with a node (i',j')->k' in X
- assign index k' to (i,j)
- else
- assign index k to (i,j) in X
- k = k + 1
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