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MatsGranvik

Riemann zeta zeros as zeros of Hermitian polynomial matrix.

Sep 12th, 2017
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  1. Clear[nn, t, n, k, M, x];
  2. nn = 8;
  3. a = N[Table[Total[Im[ZetaZero[Divisors[n]]]], {n, 1, nn}]]
  4. t[n_, 1] = 0;
  5. t[1, k_] = 0;
  6. t[n_, k_] :=
  7. t[n, k] =
  8. If[n < k,
  9. If[And[n > 1, k > 1], x - Sum[t[k - i, n], {i, 1, n - 1}], 0],
  10. If[And[n > 1, k > 1], x - Sum[t[n - i, k], {i, 1, k - 1}], 0]];
  11. M = Table[Table[t[n, k], {k, 1, nn}], {n, 1, nn}];
  12. MatrixForm[M];
  13. FullSimplify[
  14. Table[x /.
  15. Solve[Sum[(t[n, k] + a[[GCD[n, k]]])*Cos[-2*Pi*k/n], {k, 1, n}] ==
  16. 0, x], {n, 1, nn}]];
  17. Chop[Sort[Flatten[N[%]]]]
  18. x /. Solve[
  19. Det[M + Table[Table[a[[GCD[n, k]]], {k, 1, nn}], {n, 1, nn}]] == 0,
  20. x]
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