void solve(){
  string s,t,p;
  cin>>s>>t>>p;
  int freq[27]{},i=0,j=0;
  for(int i=0;i<p.size();i++){
    freq[p[i]-'a']++;
  }
  while(j<t.size()){
    if(i<s.size()&&s[i]==t[j]){
      i++;
      j++;
    }else{
      if(freq[t[j]]>0){
        freq[t[j]]--;
        j++;
      }else{
        cout<<"NO"<<"\n";
        return;
      }
    }
  }
  if(i==s.size()&&j==t.size()){
    cout<<"YES"<<"\n";
  }else{
    cout<<"NO"<<"\n";
  }
 }