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Nov 19th, 2017
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MySQL 0.27 KB | None | 0 0
  1. SELECT COU_ANNEE AS "Annee", PER_GENRE AS
  2. "Genre (Catégorie)", COUNT(per_id) AS "Nombre Candidats"
  3. FROM cc_personne
  4. JOIN cc_course ON COU_PER_ID = PER_ID
  5. WHERE PER_EQU_ID = (SELECT EQU_ID
  6. FROM cc_equipe
  7. WHERE EQU_NOM = "HES-SO Genève")
  8. GROUP BY COU_ANNEE, COU_COURSE
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