Methods) Heron´s Formula

public class Main {
    public Main() {
    }

    public static void main(String[] args) {
        double a = triangleArea(3, 3, 3);
        System.out.println("A triangle with sides 3,3,3 has an area of " + a);
        a = triangleArea(3, 4, 5);
        System.out.println("A triangle with sides 3,4,5 has an area of " + a);
        a = triangleArea(7, 8, 9);
        System.out.println("A triangle with sides 7,8,9 has an area of " + a);
        System.out.println("A triangle with sides 5,12,13 has an area of " + triangleArea(5, 12, 13));
        System.out.println("A triangle with sides 10,9,11 has an area of " + triangleArea(10, 9, 11));
        System.out.println("A triangle with sides 8,15,17 has an area of " + triangleArea(8, 15, 17));
        System.out.println("A triangle with sides 9,9,9 has an area of " + triangleArea(9, 9, 9));
    }

    public static double triangleArea(int a, int b, int c) {
        double s = (double)(a + b + c) / 2.0D;
        double A = Math.sqrt(s * (s - (double)a) * (s - (double)b) * (s - (double)c));
        A *= 100.0D;
        A = (double)((int)A);
        A /= 100.0D;
        return A;
    }
}