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Oct 20th, 2019
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  1. int Solution::maximumGap(const vector<int> &A) {
  2. vector<pair<int,int>> vp;
  3. for(int i=0; i<A.size(); i++){
  4. vp.push_back(make_pair(A[i],i));
  5. }
  6. sort(vp.begin(), vp.end());
  7. int min_till_now=INT_MAX,maxi_j=0;
  8. for(int i=0; i<A.size(); i++){
  9. if(vp[i].second<min_till_now) min_till_now=vp[i].second;
  10. if(maxi_j<vp[i].second-min_till_now) maxi_j=vp[i].second-min_till_now;
  11. }
  12. return maxi_j;
  13. }
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