Backplane Phone Screen 2

#Given an unsorted array of positive integers, return the smallest positive integer not in the array.

#[5,3,2,2,1] => 4
#[1,4,3] => 2
#[6, 5, 4] => 1

def foo(myArray):
    myArray.sort()
    count = 1
    for i in range(len(myArray)):
        if myArray[i] == count:
            if (i < len(myArray)-1) and (myArray[i+1] == myArray[i])
                continue # the next value is the same as this one
            else
                count += 1
                continue
        else:
            return count