Euler #62

def permutation(y, z):
    original = str(y)
    new = str(z)
    for x in range(10):
        if original.count(str(x)) != new.count(str(x)):
            return False
    return True

for a in range(5, 10**10):
    print(a)
    streak, y = 0, a**3
    for b in range(a+1, 10**10):
        if len(str(b**3)) > len(str(y)):
            streak = 0
            break
        if permutation(y, b**3):
            streak += 1
            if streak == 4:
                print(a**3)
                quit()