2novi nizi edna so P elem, druga so N elem

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#include <iostream>

using namespace std;

int main()
{
   int niza[100], n, i, nizaP[50], nizaN[50], j=0,k=0, elementiP=0, elementiN=0;
   cout<<"Vnesi kolku elementi kje ima nizata"<<endl;
   cin>>n;
   cout<<"Vnesi ja nizata "<<endl;
   for(i=0;i<n;i++)
   {
       cin>>niza[i];
   }
   for(i=0;i<n;i++)
   {
       if(niza[i]%2==0)//ako elementot e paren stavi go vo parnata Niza
       {
          nizaP[j]=niza[i];
          j++;
          elementiP++;
       }
       else//ako elementot e neparen staavi go neparnata niza
       {
           nizaN[k]=niza[i];
           k++;
           elementiN++;
       }
   }

  cout<<"Nizata so parni elementi e: ";
  for(j=0;j<elementiP;j++)
  {
      cout<<nizaP[j]<<" ";

  }
  cout<<endl;
  cout<<"Nizata so neparni elementi e: ";
  for(k=0;k<elementiN;k++)
  {
      cout<<nizaN[k]<<" ";
  }

    return 0;
}