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- SELECT DISTINCT CurrencyCode, Currency, NumberOfCountries
- FROM (
- SELECT cur.CurrencyCode, cur.Description AS Currency, COUNT(c.CountryName) AS
- NumberOfCountries
- FROM Currencies cur INNER JOIN Countries c
- ON cur.CurrencyCode= c.CurrencyCode
- GROUP BY cur.CurrencyCode, cur.Description
- ) AS COUNTC
- ORDER BY NumberOfCountries DESC, Currency ASC
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