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Jun 20th, 2019
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  1. boolean noName1(a: string) {
  2.  
  3. if a.Length < 2 then return true return (a[0] == a[a.Length−1])
  4. and noName1(utilityFunction(a, 1, a.Length−2))
  5. }
  6. string utilityFunction(s: string, i: integer, len: integer)
  7. {
  8. n = new char[len]
 for (j = i; j < (i + len); j++) {
  9. n[j − i] = s[j]
  10. }
  11.  
  12. return new String(n)
  13.  
  14. }
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