ahmedrahil786

Shiva Query for Email Information

Mar 22nd, 2019
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  1. SELECT
  2.  
  3. DISTINCT m.id AS memberid,
  4. m.display_name AS full_name,
  5. m.email AS email,
  6. dl.gender AS gender,
  7. sum(p.amount) as amount,
  8. r.srid as total_res
  9.  
  10. FROM members m
  11.  
  12. LEFT JOIN driver_licenses dl
  13. ON dl.member_id = m.id
  14.  
  15. LEFT JOIN payments p
  16. ON p.member_id = m.id
  17.  
  18. LEFT JOIN (
  19. select
  20. count(reservations.id) as srid,
  21. reservations.member_id as mid,
  22. reservations.state as state
  23. from reservations
  24. group by mid
  25. ) as r on r.mid = m.id
  26.  
  27. WHERE
  28. m.imaginary = 'Normal'
  29. AND m.state = 'Normal'
  30. #AND dl.gender != ''
  31. AND m.email NOT IN ('%socar.my', '%sk.com')
  32. and p.paid_type = 'card'
  33. and r.state = 'completed'
  34. GROUP BY m.id , m.display_name
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