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Nov 22nd, 2017
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  1. cost[m_, n_] := 0 /; m >= n;
  2. cost[m_, n_] := cost[m, n] =
  3. Min@Table[l + (l - m) cost[m, l - 1]/(n - m + 1)
  4. + (n - l) cost[l + 1, n]/(n - m + 1), {l, m, n}]
  5. cost[1, 100]
  6. Table[cost[1, i], {i, 1, 10}]*Range[10]
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