Anagram Check

#include<iostream>
#include<vector>
#include<map>
bool check(std::vector<int> a,std::vector<int> b)
{
    if(a.size()!=b.size())return false;
    std::map<int,int> fd;//using hashing here will decrease time complexity while increasing place required
    for(int i=0;i<a.size();++i)
    {
        fd[a[i]]++;
        fd[b[i]]--;
    }
    for(auto& x:fd)
        if(x.second!=0)return false;
    return true;
}
int main()
{
    std::cout<<check({1,2,3,4,5},{5,4,3,2,1});
}