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ccmny

letterstats

Jun 9th, 2011
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Python 0.18 KB | None | 0 0
  1. s = "be or not to be"
  2. letters = " abcdefghijklmoprstuwvxyz0123459789"
  3. s = s.lower()
  4. for letter in letters:
  5.     count = s.count(letter)
  6.     if count > 0:
  7.         print letter + " -> " + str(count)
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