CHALLENGE

Today your challenge is to write a function that takes in an Array of Arrays, and returns a String which is the markdown representation of a table of that data. Assume the first tuple is the headers for the table.

 Examples

  markdownTable([["name", "email"], ["emily", "emily@email.com"] , ["mary", "maryberry@gbbs.co.uk"]])
  // returns the String below

Example output (raw):

  |name|email|
  |---|---|
  |emily|emily@email.com|
  |mary|maryberry@gbbs.co.uk|


ASSUMPTIONS
1. The first array entered will be the header information
2. Only arrays consisting of two strings will be entered


TEST CASES



APPROACH

First deal with the headers. They need to be printed followed by a "blank line": | --- | --- |. >> Actually I think this needs to be done inside the for loop. So a for loop can be used to loop through the arrays. For each array, print each string separated by piping and a space. Write an if statement to see if it is the first array in the array - if it is, print the blankLine. If not, don't print one.

CODE

func markdownTable(groups: [[String]]) -> String {

    let header = groups[0]

    let headerToPrint = "| \(header.joined(separator: " | ")) |"

    //print(headerToPrint)

    let blankLine = "| ---- | ---- |"

    for eachArray in groups {

        if eachArray == groups[0] {
            print("| \(eachArray.joined(separator: " | ")) |\n\(blankLine)")
        } else {
            print("| \(eachArray.joined(separator: " | ")) |")
        }

    }

    print("\(headerToPrint)\n\(blankLine)")

    return "\(headerToPrint)\n\(blankLine)"
}

markdownTable(groups: [["name", "email"], ["emily", "emily@email.com"], ["mary", "maryberry@gbbs.co.uk"]])