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Jul 19th, 2014
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  1. #include<iostream>
  2. #include<stdio.h>
  3. #define ll long long
  4. using namespace std;
  5. ll n, m, k;
  6. ll get(ll a)
  7. {
  8. return (n / (a + 1)) * (m / (k - a + 1));
  9. }
  10. int main()
  11. {
  12. cin >> n >> m >> k;
  13. if(n + m - 2 < k)
  14. cout << -1;
  15. ll l, r;
  16. l = max(0ll, k + 1 - m), r = min(k, n - 1);
  17. cout << max(get(l), get(r)) << endl;
  18. return 0;
  19. }
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