Adrita

diamond pattern(*)

May 7th, 2019
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  1. #include<stdio.h>
  2. int main()
  3. {
  4. int n,i,j;
  5. scanf("%d",&n);
  6. for(i=0; i<2*n-1; i++)
  7. {
  8. if(i<n)
  9. {
  10. for(j=0; j<2*n-1; j++)
  11. {
  12. if(j<n&&j>=n-1-i)
  13. printf("* ");
  14. else if(j>=n&&j<=n-1+i)
  15. printf("* ");
  16. else
  17. printf(" ");
  18. }
  19. printf("\n");
  20. }
  21. else if(i>=n)
  22. {
  23. for(j=0; j<2*n-1; j++)
  24. {
  25. if(j<n&&j>=i-n+1)
  26. printf("* ");
  27. else if(j>=n&&j<=3*n-i-3)
  28. printf("* ");
  29. else
  30. printf(" ");
  31. }
  32. printf("\n");
  33. }
  34. }
  35. }
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