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Korobka887

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Jan 13th, 2022
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Python 0.29 KB | None | 0 0
  1. symb = '0123456789abcdef'
  2.  
  3. count = 0
  4. for i in range(4096, 65536):
  5.     n = hex(i)[2:]
  6.     if len(set(n)) == 4:
  7.         flag = True
  8.         for j in range(3):
  9.             flag = False if symb.find(n[j]) % 2 == symb.find(n[j+1]) % 2 else flag
  10.         count += 1 if flag else 0
  11.  
  12. print(count)
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