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- # Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate
- # number must exist. Assume that there is only one duplicate number, find the duplicate one.
- # You must not modify the array (assume the array is read only).
- # You must use only constant, O(1) extra space.
- # Your runtime complexity should be less than O(n2).
- # There is only one duplicate number in the array, but it could be repeated more than once.
- class Solution:
- def findDuplicate(self, nums: List[int]) -> int:
- sp = nums[nums[0]]
- fp = nums[nums[nums[0]]]
- while sp != fp:
- sp = nums[sp]
- fp = nums[nums[fp]]
- fp = nums[0]
- while sp != fp:
- sp = nums[sp]
- fp = nums[fp]
- return fp
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