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Oct 30th, 2017
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Python
0.24 KB
| None
|
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p
=
0
if
len
(
a
)
>
1
:
for
i
in
range
(
n
)
:
if
i
==
0
:
p+
=
a
[
i
]
+
abs
(
a
[
i
]
-a
[
i+
1
]
)
elif
i
>
0
and
i
<
n-
1
:
p+
=
abs
(
a
[
i
]
-a
[
i+
1
]
)
else
:
p+
=
a
[
n-
1
]
print
(
n*
2
+p
)
else
:
print
(
2
+
2
*a
[
0
]
)
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