ofcRS

12

Oct 30th, 2017
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Python 0.24 KB | None | 0 0
  1. p = 0
  2. if len(a) > 1:
  3.     for i in range(n):
  4.         if i == 0:
  5.             p+=a[i]+abs(a[i]-a[i+1])
  6.         elif i>0 and i<n-1:
  7.             p+=abs(a[i]-a[i+1])
  8.         else:
  9.             p+=a[n-1]
  10.     print(n*2+p)
  11. else:
  12.     print(2+2*a[0])
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