⇝ Given :-

Amal's age is 3 times of his son Amar.

Before 10 years Amal's age was 5 times of Amar.

⇝ To Find :-

Their Present Ages.

⇝ Solution :-

Let,

Present Age of Amal = 3x years.

Accordingly

Present Age of Amar = x years.

❒ 10 Years Ago :

Age of Amal = (3x - 10) years.

Age of Amar = (x - 10) years.

⏩ According To Question :

[tex]\bold{3x - 10 = 5(x-10)} \\[/tex]
[tex]:\longmapsto \rm - 10 = 5x - 50 \\[/tex]
[tex]:\longmapsto \rm 3x - 5x = -50 + 10 \\[/tex]
[tex]:\longmapsto \rm -2x = -40 \\[/tex]
[tex]:\longmapsto x = \frac{40}{2} \\[/tex]
[tex]:\longmapsto \Large \underline{\boxed{\bf{x = 20}}}[/tex]

So,

Age of Amal = 3x = 3 × 20 = 60 years

Age of Amar = x = 20 years

Hence,

[tex]\begin{cases}\text{\bf{Age of Amal}} = \bf{60 \ years} \\ \\\text{\bf{Age of Amar}} = \bf{20 \ years}\end{cases}[/tex]