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Mar 24th, 2017
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  1. class Solution(object):
  2. def keyboard(self,words):
  3. row1 = set('qwertyuiop')
  4. row2 = set('asdfghjkl')
  5. row3 = set('zxcvbnm')
  6. out = []
  7.  
  8. for word in words:
  9. inp = set(word.lower())
  10. for ref in [row1, row2, row3]:
  11. if inp & ref == inp:
  12. out.append(word)
  13. break
  14.  
  15. return out
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