Python/ Find Url: Python Challenge 4

import urllib

def find_the_url():
    global numero
    escape = 0
    list1 = []
    searchphrase = 'next nothing is'
    while escape == 0:
        locallist = []
        url = "http://www.pythonchallenge.com/pc/def/linkedlist.php?nothing="+str(numero)
        conn = urllib.urlopen(url)
        for line in conn.fp:
            line = line.strip()
            locallist.append(line)
        conn.close()
        text5 = '\n'.join(locallist)
        if searchphrase in text5:
            win = text5.find(searchphrase)
            list1 = []
            for a in text5[win:]:
                if a.isdigit():
                    list1.append(a)
            numero = ''.join(list1)
            print numero,"    ",text5
        else:
            print text5
            escape = 1

numero = 12345
#numero = 8022
find_the_url()

"""
look for number after 'next nothing is'
"""