FIND NO OF ROOT OF A quadratic equation ax^2+bx+c=0

# A quadratic equation ax^2+bx+c=0 has either 0, 1, 2 distinct solutions for real values of x
#Given a, b, c you should return the number of solutions to the equation.
# Python program to find roots
# of a quadratic equation
import math
# Prints roots of quadratic equation
# ax*2 + bx + x
def findRoots( a, b, c):

  # a is always positive
  if a <= 0:
    print("Invalid")
    return -1
  d = b * b - 4 * a * c
  sqrt_val = math.sqrt(abs(d))

  if d > 0:
    print("2")
  elif d == 0:
    print("1")
  else: #d<0
    print("2")

a = -1
b = 0
c = 0
findRoots(a, b, c)