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AlbertMourato

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AlbertMourato
Dec 6th, 2015
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  1. for(ll i = 2;i<=100000;i++){
  2.         for(ll j = 2; j<=500000;j++){
  3.             if(aux[i]==-1){
  4.                 i++;
  5.             }else{
  6.                 aux[i*j] = -1;
  7.             }
  8.         }
  9.     }
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