function getTokens(rawString) {
  return rawString.toLowerCase().split(/[ ,!.";:-]+/).filter(Boolean).sort();
  // Basically, the above function is implementing several methods to, in effect, standardize the information that will be provided into the "mostFrequentWord" function below.
  // 1. we are taking the argument 'rawString' and making all words contained lowercase(effectively acheiving that the words "the" and "The" will be treated the same)
  // 2. the split method is used to create a new array that removes a certain number of items that coincide with the parameters set in the regexp function. In this case, we are eliminating any punctuations.
  // 3. As mentioned above `.filter(Boolean)` removes any falsy items from the newly created array.
  // 4. Finally, the .sort method rearranges the newly created array. Because no parameters were given, the sort() method sorts the values as strings in alphabetical and ascending order.
}

function mostFrequentWord(text) {
  //this is the actual function that will be called upon to sort the 'text' to identify the mostFrequentWord.
  let words = getTokens(text);
  //here we are creating a new 'words' variable by running the provided 'text' through the 'getTokens' function we created above
  let wordFrequencies = {};
  //here we are subsequently creating an object(identified by the {}) that consist of keys (ie specific words) and values (ie 0 or 1)
  for (let i = 0; i <= words.length; i++) {
    //here is a loop statements that allows us to apply the below behaviors over the entire length of the 'words' variable.
    if (words[i] in wordFrequencies) {
      //here we are stating that if the variable (words[i]) is already in the object(wordFrequencies) then we will cycle by an increment of 1
      wordFrequencies[words[i]]++;
    }
    else {
      wordFrequencies[words[i]] = 1;
      //here we are stating that if the variable (words[i]) is not in the object then we want to add it and set it equal to 1
    }
  }
  let currentMaxKey = Object.keys(wordFrequencies)[0];
    //here we create a variable 'currentMaxKey' that consist of the keys of the wordFrequencies object that begins at the first argument
  let currentMaxCount = wordFrequencies[currentMaxKey];
    //here we create a variable 'currentMaxCount' that consist of the values of the wordFrequencies object

  for (let word in wordFrequencies) {
     //here we are looking to utilize the variable 'word' to iterate over the object 'wordFrequencies'
    if (wordFrequencies[word] > currentMaxCount) {
      currentMaxKey = word;
      currentMaxCount = wordFrequencies[word];
      //if wordFrequencies[word] is greater than the currentMaxCount then we are going to reset the value of currentMaxKey to the new 'key' value, and reassign the currentMaxCount to the new corresponding 'value'
    }
  }
  return currentMaxKey;
  //returns the word (ie key) that appears most in the provided text
}