Tortoise racing

//Two tortoises named A and B must run a race. A starts with an average speed of 720 feet per hour. Young B knows she runs faster than //A, and furthermore has not finished her cabbage.

//When she starts, at last, she can see that A has a 70 feet lead but B's speed is 850 feet per hour. How long will it take B to catch //A?

//More generally: given two speeds v1 (A's speed, integer > 0) and v2 (B's speed, integer > 0) and a lead g (integer > 0) how long will //it take B to catch A?

//The result will be an array [hour, min, sec] which is the time needed in hours, minutes and seconds (round down to the nearest //second) or a string in some languages.

//If v1 >= v2 then return nil, nothing, null, None or {-1, -1, -1} for C++, C, Go, Nim, [] for Kotlin or "-1 -1 -1".

#My_solution

fun race(v1:Int, v2:Int, g:Int):IntArray {
    // your code

    if (v1 >= v2) return intArrayOf()

    val time : Int = g * 3600 / (v2 - v1)

    return intArrayOf(time / 3600, (time % 3600) / 60, time % 60)
}

#Best_solution
fun race(v1:Int, v2:Int, g:Int):IntArray {
    return if (v1 >= v2) {
        intArrayOf()
    } else {
        val s  = (3600 * g) / (v2 - v1)
        intArrayOf( s/3600, s/60%60, s%60 )
    }
}