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Saleh127

Light OJ 1095

Sep 19th, 2021
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  1. #include <bits/stdc++.h>
  2. using namespace std;
  3. #define ll long long
  4. #define test int tt; cin>>tt; for(int cs=1;cs<=tt;cs++)
  5.  
  6. ll cm[2000][2000];
  7. ll dear[2000];
  8. ll f[2000];
  9. ll mod=1e9+7;
  10.  
  11. void fact()
  12. {
  13. ll i,j;
  14. f[0]=1;
  15. for(i=1;i<=1000;i++)
  16. {
  17. f[i]=(f[i-1]%mod * i)%mod;
  18. }
  19. }
  20.  
  21.  
  22. ll nCr(ll n,ll r)
  23. {
  24. if(r==1) return n;
  25.  
  26. if(r==n || r==0) return 1;
  27.  
  28. if(cm[n][r]!=-1) return cm[n][r];
  29.  
  30. cm[n][r]=(nCr(n-1,r-1)%mod + nCr(n-1,r)%mod)%mod;
  31.  
  32. return cm[n][r];
  33. }
  34.  
  35. ll dearrange(ll n)
  36. {
  37. if(n==1) return 0;
  38. if(n==2 || n==0) return 1;
  39.  
  40. if(dear[n]!=-1) return dear[n];
  41.  
  42. dear[n]=((n-1) * (dearrange(n-1)%mod+dearrange(n-2)%mod)%mod)%mod;
  43.  
  44. return dear[n];
  45. }
  46.  
  47. int main()
  48. {
  49. ios_base::sync_with_stdio(0);
  50. cin.tie(0);cout.tie(0);
  51.  
  52. memset(dear,-1,sizeof dear);
  53. memset(cm,-1,sizeof cm);
  54.  
  55. test
  56. {
  57. ll n,m,i,j,k,l,ans=0,mk,left;
  58.  
  59. cin>>n>>m>>k;
  60.  
  61. left=n-m;
  62.  
  63.  
  64. for(i=0;i<=left;i++)
  65. {
  66.  
  67. l=nCr(left,i);
  68. j=dearrange(n-k-i);
  69.  
  70. ans=(ans + (l*j)%mod)%mod;
  71. }
  72.  
  73. mk=nCr(m,k);
  74.  
  75. ans=(mk*ans)%mod;
  76.  
  77. cout<<"Case "<<cs<<": "<<ans<<endl;
  78. }
  79.  
  80. return 0;
  81. }
  82.  
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