Sort from behind and check what is longer

import java.util.Arrays;
//import java.util.Scanner;

public class Main {//sort from behind
    public static void reverseArray(int[] arr1 ){
        for (int i = 0; i < arr1.length/2; i++) {
        int item = arr1[i];
        arr1[i]=arr1[arr1.length-1-i];
        arr1[arr1.length-1-i] = item;
        }


    }

    public static void main (String [] Args){
        int[] arr1 = {1,2,3,4,5};
        int[] arr2 = {2,7,4,9};
        if (arr1.length==arr2.length){//check what is longer
            System.out.println("yes");
        }else{
            System.out.println("no");
        }
        System.out.println(Arrays.toString(arr1));
        reverseArray(arr1);
        System.out.println(Arrays.toString(arr1));
    }
}