Check if is a name or not, (WTF), py 3.x

# coding: utf-8

def letras():
    """
        RECOGNIZES LETTERS IN THE WORD AND REMEMBER THEM IN A LIST, IF THEM COUNTED MORE THAT 2 TIMES. :D
    """
    names = ["Pedro", "Luiza", "Matheus", "Bruno", "Daniele", "Reni", "Fatima", "Isabela", "Ana", "João", "Vitor"]
    chars, most_used = [], []
    for name in names:
        for char in name:
            if name.count(char) >= 1:
                chars.append(char)
    for char in chars:
        if chars.count(char) >= 2 and char not in most_used:
                most_used.append(char)
    return list(", ".join(most_used))


def nomes(entrada='reni'.title()): # entry default is my name, :p
    """
        GIVE A SCORE FOR A ENTRY, IF MORE THAT .05 (IS A NAME), ELSE NOT IS A NAME
    """
    pts = .0
    letras_mais_usadas = letras()
    if len(entrada) > 1:
        for letra in letras_mais_usadas:
            if letra in entrada:
                pts += .025
    else:
        quit()
    return pts if pts > .01 and pts <= 0.7 else False

# Check score only, HEUIAHEUIAHIUE, I DON'T WANNA CREATE A FUNCTION FOR THIS... Anonimy function is better
check_real = lambda : True if nomes() > 0.05 else False
print(check_real()) # Only print the result. :D