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- Oppgave 4 – Har ingen anelse
- a)
- SELECT * FROM movie
- ELLER
- SELECT * FROM movie, casting, actor
- WHERE movie.id = casting.movieid AND casting.actorid = actor.id
- b)
- SELECT title, movie.id, yr FROM movie
- ELLER
- SELECT title, movie.id, yr FROM movie, casting, actor
- WHERE movie.id = casting.movieid AND casting.actorid = actor.id
- ELLER
- SELECT DISTINCT title, movie.id, yr FROM movie, casting, actor
- WHERE movie.id = casting.movieid AND casting.actorid = actor.id
- c) SELECT id, title, yr
- FROM movie
- WHERE yr = '1962'
- d) SELECT title, yr
- FROM movie
- WHERE title = 'citizen kane'
- e) SELECT id, title, yr
- FROM movie
- WHERE title LIKE '%star trek%'
- ORDER BY yr DESC
- f) SELECT * FROM movie, casting, actor WHERE movie.id = casting.movieid AND casting.actorid = actor.id AND title IN('another year','arthur') // Fant ut at IN er mer effektivt enn mange AND queries.
- g) SELECT movie.id, title, yr, actor.id, actor.name FROM movie, casting, actor WHERE movie.id = casting.movieid AND casting.actorid = actor.id AND title IN('another year','arthur')
- h) SELECT * FROM actor
- i) SELECT name FROM actor
- WHERE id NOT IN (SELECT actorid FROM casting)
- j) SELECT * FROM movie, casting
- WHERE movie.id = casting.movieid AND casting.actorid IS NULL
- Alle filmene har skuespillere håper jeg. Ellers er svaret feil, vanskelig å verifisere.
- k) SELECT * FROM movie, casting
- WHERE movie.id = casting.movieid AND casting.actorid IS NULL AND movie.yr = '2011'
- l) SELECT id, name FROM actor
- WHERE name = 'Harrison Ford'
- m) SELECT id, name FROM actor
- WHERE name LIKE '%ford'
- n) SELECT id, name FROM actor
- WHERE name LIKE '% ford' //’%(mellomrom)ford’
- o) Han er registrert to ganger
- p) SELECT casting.movieid, actor.name FROM casting, actor
- WHERE casting.actorid = actor.id AND actor.name = 'Harrison Ford'
- q) SELECT movie.title, actor.name FROM movie, casting, actor
- WHERE movie.id = casting.movieid AND casting.actorid = actor.id AND actor.name = 'Harrison Ford'
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