Printing 2d level to screen without clearing the screen, efficiently
import os
import time
import random
clear = lambda: os.system('clear')

g = '33[32m' + '# '
t = '33[31m' + '^ '
l = [g, g, g, g, g, g,
     g, g, g, g, g, g,
     g, g, g, g, g, g,
     g, g, g, g, g, g,
     g, g, g, g, g, g,
     g, g, g, g, g, g]

def level():
    i = 0
    while i < 1000:
        print l[0] + l[1] + l[2] + l[3] + l[4] + l[5]
        print l[6] + l[7] + l[8] + l[9] + l[10] + l[11]
        print l[12] + l[13] + l[14] + l[15] + l[16] + l[17]
        print l[18] + l[19] + l[20] + l[21] + l[22] + l[23]
        print l[24] + l[25] + l[26] + l[27] + l[28] + l[29]
        print l[30] + l[31] + l[32] + l[33] + l[34] + l[35]
        i += 1

        for b in l:
            ch = round(random.random())
            if ch:
                l[l.index(b)] = g
            else:
                l[l.index(b)] = t
        clear()
level()