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Nov 19th, 2018
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  1. k=0;
  2. for(j=0;j<n;j++)
  3. {
  4. A[j]=B[j]+C[j]; /*S1*/
  5. C[j]=A[j]/D[j]-(log 10(E[j]*F[j]); /*S2*/
  6. K=k+A[j]+C[j]; /*S3*/
  7. }
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