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- clear;clc;
- % user input
- % volba = menu('Title', 'p1', 'p2', 'p3'); % zobrazeni menu, a ulozeni vysledku
- % promenna = 5;
- % vstup = input('Zadej cislo voe: '); % muze zadat co chce though (cislo, [vektor], [matici;2], funkci,
- % 'string', pi, e, 2 * pi, sin(konst), cos(promenne)...)
- vstup = input('Zadej cislo pls: ');
- if vstup < 0
- disp('Zadane cislo je zaporne')
- elseif vstup > 0
- disp('Zadane cislo je kladne')
- else
- disp('Zadane cislo je nula')
- end
- vstup1 = menu('Vyber spravne policko a vyhraj !!!!', '#1', '#2', '#3');
- switch vstup1
- case 1
- menu('Smula', 'Ok');
- case 2
- menu('Smula', 'Ok');
- case 3
- menu('Gratulace, vyhral jsi', 'Ok');
- otherwise
- for k = 1:10
- x = menu('Uz to nedelej', 'ok?');
- end
- end
- % -------------------------------------------------------------
- clear;clc;
- %j++
- for j = 1:2:20
- disp(j)
- end
- %j--
- for j = 20:-2:1
- disp(j)
- end
- for k = [2 4 7 1 2 4]
- disp(k);
- end
- for k = [2 4 7 1 2 4]' % sloupcovy vektor, pri tisku bude bez mezer mezi prvky
- disp(k); % je to tak protoze pri kazde iteraci bere SLOUPEC matice,
- end % tzn. u vektoru probehne 1 iterace
- for m = linspace(1,3,6)
- disp(m);
- end
- % tisk matice po sloupcich
- for M = [1 2 3; 4 5 6]
- disp(M);
- end
- % tisk matice po prvcich
- A = [7 8 9; 1 2 3];
- for i = 1:2
- for j = 1:3
- disp (A(i,j));
- end
- end
- % soucet hodnot matice
- B = [7 8 9; 1 2 3];
- soucet = 0;
- for i = 1:2
- for j = 1:3
- soucet = soucet + A(i,j);
- end
- end
- str = ['soucet prvku je ', num2str(soucet)];
- disp(str);
- % CTRL + C => ukonceni behu programu
- in = input('Zadej cele cislo: ');
- tic
- while (in < 69)
- in = in + 1;
- end
- X = ['Je tohle cos zadal? ', num2str(in)];
- toc
- disp(X);
- % kontrola vstupu
- vstup = input('Zadej cislo od 0 do 15: ');
- while (vstup < 0 || vstup > 15)
- disp('0 AZ 15 VOLE');
- vstup = input('Zadej cislo od 0 do 15');
- end
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