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- SELECT t.resource_id, t.version, t.value
- FROM secrets t
- JOIN (
- SELECT resource_id, MAX(version) AS version
- FROM secrets
- GROUP BY resource_id
- ) max_versions ON (
- max_versions.resource_id = t.resource_id
- AND max_versions.version = t.version
- )
- WHERE t.resource_id IN ?
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