avoids110433

'''
Created on 04/11/2014
avoids
Proven and tested on python 3.3.3
@author: A01221672
'''
def avoids(word,forbidden):
    c1 = 0
    for letter in range(len(word)):
        if word[letter] == forbidden or word[letter].upper():
            c1 = c1 + 1
    if c1 == 0:
        print("True")
    else:
        print("False")

avoids("Edgar","e")