import re
from collections import OrderedDict
def latex2func(s, udict=OrderedDict()):
    class make_xlat(object):
        def __init__(self, *args, **kwargs):
            self.adict = OrderedDict((
                    (r'\left'  , ''),
                    (r'\right' , ''),
                    (r'\cdot'  , '*'),
                    ('^'       , '**'),
                    (' '       , ''),
                    ('{'       , '('),
                    ('}'       , ')'),
                    (r'(\d+)([A-Za-z]\d*\w*)' , r'\1*\2'),
                    (r'\((\d+)\)' , r'\1'),
                    ))
            self.adict.update(*args, **kwargs)
            self.grp_lookup = self.make_grp_lookup()
            self.rx = self.make_rx()
        def make_grp_lookup(self):
            grps = {}
            for k,v in self.adict.items():
                i = max(grps.keys())+1 if grps else 0
                grps.update({i+j: k for j in range(len(re.findall(r'\\\d+', v)))})
            return grps
        def make_rx(self):
            l = []
            for k, v in self.adict.items():
                if not re.search(r'\\\d+', v):
                    l.append(''.join(map(re.escape, k)))
                else:
                    l.append(k)
            return re.compile('|'.join(l))
        def one_xlat(self, match):
            try: # Simple string replacement
                return self.adict[match.group(int(0))]
            except: # Subpattern group replacement
                i, m = zip(*[(i, v) for i, v in enumerate(match.groups()) if v is not None])
                t = self.adict[self.grp_lookup[i[0]]] # Assumes all indicies are the same, if not, something went wrong
                for i, g in enumerate(m):
                    t = t.replace(r'\{}'.format(i+1), g)
                return t
        def __call__(self, txt):
            return self.rx.sub(self.one_xlat, txt)


    translate = make_xlat(udict)
    while translate(s) is not s:
        s = translate(s)
    s = s.split('=')
    args = re.sub(r'.*\((.*)\)', r'\1', s[0])
    eqn = s[1]
    return eqn