def pseudopasswd(instr, limit):
    # null pad odd length string
    if len(instr) % 2 == 1:
        instr = instr + chr(0)
    charset = "aAbBcCdDeEfFgGhHiIjJkKlLmMnNoOpPqQrRsStTuUvVwWxXyYzZ0123456789."
    t1 = 0
    t2 = 0
    t3 = 0
    t4 = 0
    out = []
    for i in range(limit):
        if i == len(instr)/2:
            break
        a = ord(instr[2*i])
        b = ord(instr[2*i+1])
        t3 = t3 + b & 0xffffffff
        t5 = t3 ^ t2 & 0xffffffff
        if (t5 == 0):
            t5 = 0xe0b8585b
        t1 = t4 + a ^ t1
        t1 = t1 & 0xffffffff
        if (t1 == 0):
            t1 = 0x9e3779b9
        t2 = ((t5 & 0xffff) * 0x9069) + (t5 >> 0x10) & 0xffffffff
        t1 = ((t1 & 0xffff) * 18000) + (t1 >> 0x10) & 0xffffffff
        t5 = (t2 << 16) + t1 & 0xffffffff
        t6 = t5 >> 13 ^ (t4 + a - t3) - t5
        t6 = t6 & 0xffffffff
        t7 = t6 << 8 ^ (t3 - t5) - t6
        t7 = t7 & 0xffffffff
        t4 = t7 >> 13 ^ (t5 - t6) - t7
        t4 = t4 & 0xffffffff
        t3 = t4 >> 12 ^ (t6 - t7) - t4
        t3 = t3 & 0xffffffff
        t6 = t3 << 16 ^ (t7 - t4) - t3
        t6 = t6 & 0xffffffff
        t5 = t6 >> 5 ^ (t4 - t3) - t6
        t5 = t5 & 0xffffffff
        t4 = t5 >> 3 ^ (t3 - t6) - t5
        t4 = t4 & 0xffffffff
        t3 = t4 << 10 ^ (t6 - t5) - t4
        t3 = t3 & 0xffffffff
        tmp = (t5 - t4) - t3 & 0xffffffff
        idx = (t3 >> 0xf ^ tmp ) % 0x3f
        out.append(charset[idx])
    return ''.join(out)

limit = 30
input = "Pack my box with five dozen liquor jugs. 1234567890"
result = pseudopasswd(input, limit)
print(result)