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Jun 26th, 2017
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Python
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def
pd_sum2
(
n
)
:
pd
=
1
for
x
in
xrange
(
2
,
int
(
n**
.5
)
)
:
if
n % x
==
0
:
pd +
=
x + n//x
x +
=
1
if
x*x
==
n:
pd+
=
x
return
pd
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